I'm so confused!

Discussion in 'The Spam Zone' started by Keychain System, Oct 1, 2008.

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  1. Keychain System Two?!

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  2. Advent 【DRAGON BALLSY】

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    It's the square root of a negative number (i.e. the square root of -1 = i, the square root of -4 = 2i, etc.).
     
  3. Keychain System Two?!

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    I know that, but other than that, I know NOTHING about imaginary numbers! See, I decided to do some research on them, which my math teacher warned me not to do, so of course I did. Just to enlighten myself. That's when I got confuzzlinated (Lol, Firefox thinks that's a word).
     
  4. What? 『 music is freedom 』

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    I think that you need limits on your curiousity or else your brain will asplode.
     
  5. Advent 【DRAGON BALLSY】

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    Yea, the Wikipedia article was no doubt written by a math nerd. That's really high-end stuff...
     
  6. Sonic the Hedgehog The Blue dude is back!!

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    wtf booooooooooooooooooooooooooooooooooooooooooooom
     
  7. Explode Who?!

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    These numbers are imaginary because it's impossible to square a number and get a negative result. That's all you need to know XD
     
  8. Keychain System Two?!

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    Seriously? Now i feel stupider than when I read the article. :stupid:
     
  9. Jube Formerly Chuck's

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    TROMBEddddd
     
  10. Toshi Banned

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    This is a whole unit we are examined in this year. i^2 = -1 is just the elementary attribute...
     
  11. Explode Who?!

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    Yeah, this is true. When I said:

    I meant that it's all you need to know in order to understand what they are. You still need to know how to use them. You need to apply them in different situations, but if you know this, you should be okay:

    i = the square root of -1

    i^2 = -1

    i^3 = -1 times the square root of -1

    i^4 = 1
     
  12. Toshi Banned

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    These are true but you don't say it like this. You don't replace i with s.r. of -1
    It's:

    i^0 = 1
    i^1 = i
    i^2 = -1
    i^3 = i^2 = -1
    i^4 = i^3 * i = 1
    An the list goes on.
    But there are more things you should know, like z*\bar{z} = x^2 + y^2 or Re(z) = z +\bar{z} / 2 and Im(z) = z - \bar{z} / 2i etc.
     
  13. Deathsight44 Kingdom Keeper

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    Its just anouther form of math which we will never use in our lives......
     
  14. TheMagicalMisterMistoffelees Professional Crazy

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    I got that, until there. You lost me there.
     
  15. Toshi Banned

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    If
    z = x + yi
    then
    \bar{z} = x - yi
    Easy stuff, but I don't want to analyse it more or explain other stuff to you, 'cause you'll just get more confused. There are more things to know if you want to use the -babelfish doesn't translate the name of these numbers-. But I wish they would put these in the final exams :(
     
  16. zexykupo Gummi Ship Junkie

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    You're not the only one who's confused over here...
     
  17. TheMagicalMisterMistoffelees Professional Crazy

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    So, if \bar{z}= x^2 + y^2, then z= x^2 - y^2?
     
  18. Toshi Banned

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    No... ok look how it is:
    z*\bar{z} = (x + yi)*(x - yi) = x^2 - xyi + xyi -y^2*i^2 = x^2 + y^2
    Got it?
     
  19. TheMagicalMisterMistoffelees Professional Crazy

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    Yeah, you basically used the FOIL method to multiply z*\bar{z}, after you translated it into (x + yi)*(x - yi), you got (x*x) + (x*yi) + (x*(-yi)) + ((y*y)*(i*i)), and it's basic simplification from there, right?
     
  20. Toshi Banned

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    I'm not sure what FOIL is (I think you mean the attribute used when multiplying and don't get me wrong but I just haven't heard the word in English) but you got it right.
     
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