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  1. Kubo
    u = 1 + r + r^2 + r^3.... (1)
    u*r = r + r^2 + r^3 + r^4.... (2)

    (1)-(2)=u-u*r= (1 + r + r^2 + r^3....) - ( r + r^2 + r^3 + r^4....) = 1
    Post by: Kubo, Aug 12, 2012 in forum: The Spam Zone
  2. Kubo
    I don't know what you're talking about and why you think VLC sucks but it does have Hi10p support. And it's the most flexible and customizable media player out there, unless you mean it doesn't have a customizable interface, which is not a good reason to say it sucks anyways.
    Post by: Kubo, Aug 11, 2012 in forum: The Spam Zone
  3. Kubo
    What sorry, don't apologize to anyone, post whatever you like if someone's got a problem then all you have to do is post this and you're done.
    Post by: Kubo, Aug 11, 2012 in forum: The Spam Zone
  4. Kubo
    When I say you lack basic calclulus knowledge, you think that I say it because I don't know what to tell you. This formula is used in geometric series that converge and has a proof.
    r is the common ratio; 1/10.
    If you want to see what 0.333 does then you need to go to the formula and see what happens. Not every series =1. In fact this series converge to 3/7, if I did the calculations correctly.
    Post by: Kubo, Aug 11, 2012 in forum: The Spam Zone
  5. Kubo
    I suppose your computer is a high-end machine and you have no problems with video playback and lagging. Get an average computer and you'll see how valuable that media player is. With countless features, it is the most powerful video software currently.
    Post by: Kubo, Aug 11, 2012 in forum: The Spam Zone
  6. Kubo
    Hilarious rap battles... thanks for reminding.
    Post by: Kubo, Aug 11, 2012 in forum: The Spam Zone
  7. Kubo
    VLC is using its built-in codecs, that's why it's so great.
    But if you want a modern media player you could use TotalMedia Theatre 5.
    Post by: Kubo, Aug 11, 2012 in forum: The Spam Zone
  8. Kubo
    Clearly you have absolutely no idea what you're talking about... What don't I know about? You assumed I'm the training guy, how does this make me not knowing how things work lol? Are you trying to start an argument with yourself? That's ****ed up! If you want just let me know, and in a few months you will have a brother (or perhaps sister) with whom you can argue any time you want. =]
    Post by: Kubo, Aug 10, 2012 in forum: The Spam Zone
  9. Kubo
    Not realy. If you don't know how things work, then don't make assumptions.
    Post by: Kubo, Aug 10, 2012 in forum: The Spam Zone
  10. Kubo
    Don't compare me with other mathematicians.
    Post by: Kubo, Aug 10, 2012 in forum: The Spam Zone
  11. Kubo
    Psst chill dude, don't be so sure about that.
    Post by: Kubo, Aug 9, 2012 in forum: The Spam Zone
  12. Kubo
    I took 3 times differential calculus 1 before I passed it, if I am to explain it "in great detail" I might as well write a book about it and publish it now.
    You lack basic knowledge in maths (limits and their properties- infinity, convergence/divergence) and I am not the one to teach you them.
    Post by: Kubo, Aug 9, 2012 in forum: The Spam Zone
  13. Kubo
    One word: convergence.
    Post by: Kubo, Aug 9, 2012 in forum: The Spam Zone
  14. Kubo
    No, you have to distinguish infinity from numbers. Infinity is not a number, you can't add one more 9 in a number with infinite digits and make it bigger than before. 0,999... is a series as I said earlier and this is the only way it can be accurately expressed. The other proofs you mentioned earlier that it equals 1 are not exactly valid.
    Post by: Kubo, Aug 9, 2012 in forum: The Spam Zone
  15. Kubo
    The above example in programming is wrong because you have finite digits however you need to create a series to be accurate in this case.
    Anyways... this 0.999 youre talking about is the series of Σ(9/10^n), n=1->oo (which is, 9/10 + 9/100 + 9/1000 + 9/10000 +...) therefore

    http://upload.wikimedia.org/wikipedia/en/math/5/6/9/56949181a290ce561f27bd550a720392.png
    Post by: Kubo, Aug 9, 2012 in forum: The Spam Zone
  16. Kubo
    First find x^2 and y^2 then add them to create a circle which has a radius of 1...
    then we need to calculate 3 double integrals, M, Mx and My. all of them will have both integrals' bounds from 0 to 2π, and also it doesn't matter if integrate x or y first (fubini), we will choose whichever is easier.
    For M: the function inside will just be d, and we integrate that twice.
    For Mx: the functio inside will be d*y
    For My: the function inside will be d*x

    The center of mass will have coordinates x=My/M and y=Mx/M

    I probably am wrong in the bounds of the integrals because I haven't really gotten into multivariable integrals and always mess up the bounds. Most times I put them randomly :P .
    Post by: Kubo, Aug 9, 2012 in forum: The Spam Zone
  17. Kubo
    The clock system is actually Z12, and this equation is true in all subgroups of Z12: Z2, Z3, Z4 and Z6. /nerd
    Post by: Kubo, Aug 8, 2012 in forum: The Spam Zone
  18. Kubo
    Oh, in this case...
    Post by: Kubo, Aug 8, 2012 in forum: The Spam Zone
  19. Kubo
    It is true in the field Z2, of integers modulo 2.
    Post by: Kubo, Aug 8, 2012 in forum: The Spam Zone
  20. Kubo
    Facebook is successfully making people stupider.
    Post by: Kubo, Aug 8, 2012 in forum: The Spam Zone